Question

Petunia needs 66.48 grams of potassium hydroxide (KOH) to run a reaction in class. How many moles of potassium hydroxide does she need? Please round your answer to two digits after the decimal point, and remember to include correct, complete units (including substance formula).

Answer 1

Petunia needs 1.19 moles of potassium hydroxide (KOH) to run her class reaction.

Step-by-step explanation:

To calculate the number of moles of potassium hydroxide (KOH) needed, we use the molar mass of KOH, which is approximately 56.11 g/mol. By dividing the mass of KOH required for the reaction (66.48 grams) by its molar mass, we can find the moles needed:

Number of moles = Mass in grams ÷ Molar mass

Number of moles = 66.48 g ÷ 56.11 g/mol

This gives:

Number of moles ≈ 1.185 moles

Rounding to two decimal places, Petunia needs 1.19 moles of KOH.

Thus, Petunia needs 1.19 moles of KOH to run her class reaction.

Answer 2

1.19mole

Step-by-step explanation:

Given parameters:

Mass of potassium hydroxide , KOH = 66.48g

Unknown:

Number of moles of KOH = ?

Solution:

To solve this problem, we need to use the expression below;

Number of moles =
`(mass)/(molar mass)`

Molar mass of KOH = 39 + 16 + 1 = 56g/mol

Number of moles =
`(66.48)/(56)` = 1.19mole