Answer:
![W_(max) =Q_C((T_H)/(T_C) - 1)](https://img.qammunity.org/2020/formulas/physics/college/1t0ynzh04oqs47pp04iy7j4ziyt48g4727.png)
Step-by-step explanation:
given,
Temperature of heat engine operate between
Th (temperature in hot reservoir) and Tc(temperature in cold reservoir)
amount of heat released to = Qc
to find maximum amount of work = ?
now,
efficiency of heat engine
![\eta = 1 - (T_C)/(T_H) = 1 -(Q_C)/(Q_H)](https://img.qammunity.org/2020/formulas/physics/college/ypa6ubcgy89l08lnn4mkv1uakkw73vhf8a.png)
now,
![(T_C)/(T_H) = (Q_C)/(Q_H)](https://img.qammunity.org/2020/formulas/physics/college/hmy3ktxw10t6gee3o2zv87nog5jyc9krkz.png)
![Q_H= (T_H)/(T_C) Q_C](https://img.qammunity.org/2020/formulas/physics/college/bii6531ski7wzpyvauepwafwxdujc0yypp.png)
maximum work =
![W_(max) =(T_H)/(T_C) Q_C - Q_C](https://img.qammunity.org/2020/formulas/physics/college/rccg5sv1lenm33j6nue0kfyae83sx77rwe.png)
![W_(max) =Q_C((T_H)/(T_C) - 1)](https://img.qammunity.org/2020/formulas/physics/college/1t0ynzh04oqs47pp04iy7j4ziyt48g4727.png)
above expression gives the expression of maximum amount of work.