192k views
3 votes
A puck company wants to sponsor the players with the 10% quickest goals in hockey games. The times of first goals are normally distributed with a mean of 12.56 minutes and a standard deviation of 4.91 minutes. How fast would a player need to make a goal to be sponsored by the puck company?

a. 6.27 minutes
b. 18.85 minutes
c. 17.47 minutes
d. 7.65 minutes

1 Answer

5 votes

Answer:

a. 6.27 minutes

Explanation:

Assuming a normal distribution. In order to be sponsored, a player must have a z-score corresponding to the 10th percentile of the normal curve.

At the 10th percentile, the z-score is -1.28.

Mean = 12.56 minutes

Standard Deviation = 4.91 minutes

The minimum value of X required is:


z=(X-\mu)/(\sigma)\\ -1.28=(X-12.56)/(4.91)\\X= 6.27\ minutes

The player would need to make a goal within 6.27 minutes to be sponsored by the puck company

User Muhammed Fasil
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories