Question

The second-order bright fringe in a single-slit diffraction pattern is 1.35 mm from the center of the central maximum. The screen is 75 cm from a slit of width 0.838 mm. Assuming monochromatic incident light, calculate the wavelength. Answer in units of nm.

Answer 1

The wavelength is 754.2 nm.

Step-by-step explanation:

Given that,

Diffraction pattern y= 1.35 mm

Width = 0.838 mm

Distance D= 75 cm

We need to calculate the wavelength

Using formula of diffraction pattern

`y=(m\lambda D)/(d)`

`\lambda=(yd)/(mD)`

Where, y = diffraction pattern

m = order

d = width

D = distance

Put the value into the formula

`\lambda=(1.35*10^(-3)*0.838*10^(-3))/(2*75*10^(-2))`

`\lambda=7.542*10^(-7)\ m`

`\lambda=754.2\ nm`

Hence, The wavelength is 754.2 nm.