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Consider that a certain gene is a maternal effect gene and that the allele for dark brown pigment is incompletely dominant to the allele for no pigment (white). The incomplete dominant phenotype is light tan. If a heterozygous female is crossed with heterozygous male, what will be the phenotypic ratio of the progeny?

User Wakeel
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1 Answer

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Answer:

BB - Dark brown color - (1/4)

Bb - light tan (due to incomplete dominance) - (2/4 or 1/2)

bb - white color - (1/4)

Step-by-step explanation:

Let the allele for dark brown pigment be represented by "B"

And the let allele for white (no pigment) be represented by "b"

Due to incomplete dominance, the phenotype of heterozygous species would be "light tan"

Genotype of heterozygous female - Bb

Genotype of heterozygous male - Bb

Bb * Bb

BB, Bb, Bb, bb

BB - Dark brown color - (1/4)

Bb - light tan (due to incomplete dominance) - (2/4 or 1/2)

bb - white color - (1/4)

User Ruben Miquelino
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