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It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportation researcher wants to determine if the statement made in the advertisement is false. She randomly test drives 34 small cars at 65 miles per hour and records the braking distance. The sample average braking distance is computed as 114 feet. Assume that the population standard deviation is 24 feet. (You may find it useful to reference the appropriate table: z table or t table) State the null and the alternative hypotheses for the test. H_0:mu = 120: H_A: mu notequalto 120 H_0:mu 2 greaterthanorequalto 120: H_A mu < 120 H_0: mu lessthanorequalto 120: H_A: mu > 120

1 Answer

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Answer:
H_0:\mu=120


H_A:\mu\\eq120

Explanation:

Let
\mu denotes the average braking distance for a population of small car.

Given : It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet.

i.e.
\mu=120

Objective of test : Whether the statement made in the advertisement is false

i.e.
\mu\\eq120

Since '=' signs is contained by Null hypothesis and alternative hypothesis is against it.

So the null and the alternative hypotheses for the test will be:


H_0:\mu=120


H_A:\mu\\eq120

User ErikL
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