Question

A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a rate of 3.63 kg/s. The exhaust gases are ejected at 317 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N.

Answer 1

The thrust of the jet engine is 4188.81 N.

Step-by-step explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

`(dM)/(dt)=(dM_(a))/(dt)+(dM_(f))/(dt)`

Put the value into the formula

`(dM)/(dt)=53.3+3.63`

`(dM)/(dt)=56.93\ kg/s`

We need to calculate the thrust of the jet engine

Using formula of thrust

`T=(dM)/(dt)u-(dM_(a))/(dt)v`

Put the value into the formula

`T=56.93*317-53.3*260`

`T=4188.81\ N`

Hence, The thrust of the jet engine is 4188.81 N.