Answer:
The shirt cannot be more expensive than $40
Explanation:
So, the budget here is $140
Let, the price of the shirt be x, so since the jacket is 2 times the price of the shirt :
![cost = 2x](https://img.qammunity.org/2020/formulas/mathematics/high-school/bd1nuyp9kwci9npknz07dtvpfsp2ewedgb.png)
But the other condition is that it is 20 dollars more than twice the shirt so we get:
![cost = 2x +20](https://img.qammunity.org/2020/formulas/mathematics/high-school/tgei6ts1rycothv5lnuu540yb60r2mtrqr.png)
Then the cost of the jacket and the shirt should not be more than $140 so:
![x+2x+20 = 140\\\\3x+20 =140](https://img.qammunity.org/2020/formulas/mathematics/high-school/e665eprsu6xdcefgtla76d6ym62t60zrj7.png)
So, to find the highest possible cost we solve for x:
![3x+20 =140\\3x = 120\\x = 40](https://img.qammunity.org/2020/formulas/mathematics/high-school/eva32ggkmawrqnx4tvs9gewygytnxtvtgk.png)