46.1k views
3 votes
Beyond what point must an object be squeezed for it to become a black hole

User Wave
by
5.5k points

1 Answer

4 votes

Answer:

Condition


(m)/(R) \geq (c^(2) )/(2*g)

Step-by-step explanation:

Basically black hole is an object from which light rays can not escape it means to go out from gravitational field , that body should thrown with speed greater then light.

Let's do some calculation

Gravitational potential at surface =
-(G*M*m)/(R)

If we give kinetic energy equal to magnitude of Potential energy as on surface it will escape.


(m*v^(2) )/(2) =
-(G*M*m)/(R)


(m)/(R) =(c^(2) )/(2*G)

It will be more better for black hole if above ratio (analogous to density ) is more then above calculated

User Kamran Kausar
by
6.1k points