Question

A taxi driver had 50 fares to and from the airport last Monday. The price for a ride to the airport is $10, and the price for a ride from airport is $5. The driver collected a total of $375 for the day.

Answer 1

Number of Fares to airport is 25 and number of fares from airport is 25.

Explanation:

Given:

Total Number of fares =50

Let number of fares to airport be x.

Let number of fares from airport be y.

hence the equation can be framed as;

`x+y=50 \ \ \ \ equation \ 1`

Also Given

Total Money Collected = $375

Cost to airport = $10

Cost from Airport = $5

Total Money Collect is equal to Cost to airport multiplied by number of Fares to airport plus Cost from airport multiplied by number of Fare from airport.

`10x+5y=375`

Dividing by 5 on both side we get;

`2x+y = 75 \ \ \ \ equation \ 2`

Now Subtracting equation 1 from 2 we get;

`(2x+y)-(x+y)=75-50\\2x+y-x-y=25\\x=25`

Substituting the value of x in equation 1 we get;

`x+y=50\\25+y=50\\y=50-25\\y=25`

Hence Number of Fares to airport is 25 and number of fares from airport is 25.