Question

Balance

NaHCO3(s) --> Na2CO3 (s) + H2O (g) + CO2 (g)

Determine how much baking soda you will need to start with in order to produce 2.50 g of sodium carbonate

Answer 1

Mass = 3.36 g

Step-by-step explanation:

Given data:

Mass of sodium carbonate produced = 2.50 g

Mass of baking soda required = ?

Solution:

Chemical equation:

2NaHCO₃ → Na₂CO₃ + H₂O + CO₂

Number of moles of sodium carbonate:

Number of moles = mass/ molar mass

Number of moles = 2.50 g / 106 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of sodium carbonate and baking soda.

Na₂CO₃ : NaHCO₃

1 : 2

0.02 : 2×0.02 = 0.04 mol

Mass of baking soda:

Mass = number of moles × molar mass

Mass = 0.04 mol× 84 g/mol

Mass = 3.36 g