Question

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate the amount of Ga ( s ) that can be deposited from a Ga ( III ) solution using a current of 0.520 A that flows for 20.0 min .

Answer 1

0.150 g

Step-by-step explanation:

First, we will write the reduction half-reaction to produce Ga(s)

Ga³⁺(aq) + 3 e⁻ → Ga(s)

We can establish the following relations:

• 1 min = 60 s
• 1 A = 1 c/s
• 1 mole of e⁻ has a charge of 96468 c (Faraday's constant)
• 1 mole of Gas(s) is deposited when 3 moles of e⁻ circulate.
• The molar mass of Ga is 69.72 g/mole.

The mass of Ga(s) deposited when a current of 0.520 A flows for 20.0 min is:

`20.0min.(60s)/(1min) .(0.520c)/(s) .(1mol/e^(-) )/(96468c) .(1molGa)/(3mol/e^(-)) .(69.72gGa)/(1molGa) =0.150gGa`