Answer:
21.9m/s²
Step-by-step explanation:
Given parameters:
Mass of the physics student = 73kg
Net force = 1600N
Unknown:
The acceleration at this point = ?
Solution:
To solve this problem, we apply a knowledge of Newton's second law of motion which is mathematically expressed as;
F = m a
F is the friend
m is the mass
a is the acceleration
1600 = 73 x a
a = 21.9m/s²