Question

a 9.0-kg crate rests on a frictionless surface. it then experiences a net horizontal force of 45. newtons. what is the resulting acceleration of the crate?

Answer 1

5m/
`s^(2)` .

Step-by-step explanation:

Mass of the crate (m) = 9.0 Kg

Horizontal force applied to the crate(F) = 45 N .

Now,

According to the Newton's Law's of motion ,

F = ma , where a represents the acceleration of body of mass m when subjected to the horizontal force F under frictionless conditions .

Thus,

45 = 9a

a = 5 m/
`s^(2)` .

Thus , the resulting acceleration of the crate will be 5m/
`s^(2)` .