Question

Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample of an unknown HNO 3 solution required 45.1 mL of 0.200 M Ba ( OH ) 2 for complete neutralization. What is the concentration of the HNO 3 solution?

Answer 1

To determine the concentration of the HNO3 solution, calculate the number of moles and divide by the volume of the solution.

Step-by-step explanation:

In order to determine the concentration of the HNO3 solution, we can use the stoichiometry of the neutralization reaction. First, we can calculate the number of moles of HNO3 using the volume and molarity of the Ba(OH)2 solution that was required for neutralization. Then, using the balanced chemical equation, we can determine the number of moles of HNO3. Finally, we can divide the moles of HNO3 by the volume of the HNO3 solution to obtain its concentration.

Answer 2

The concentration of the HNO3 solution is 0.150 M

Step-by-step explanation:

Step 1: Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

Step 2: The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

Step 3: Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

Step 4: Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

Step 5: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M