Question

2.
4d^2 + 8d + 3-0
a. (0.25, -4.5)
b. f-0.35)
c. (-0.5, -1.5) please help me​

Answer 1

C. -0.5, -1.5

Explanation:

Given equation

`4d^2+8d+3=0`

To solve for
`d`

As the above equation is of 2nd degree, so its a quadratic equation. We can solve is by using quadratic formula.

For a quadratic equation
`ax^2+bx+c=0`

`x=(-b\pm√(b^2-4ac))/(2a)`

So, for
`4d^2+8d+3=0`

`d=(-8\pm√(8^2-4(4)(3)))/(2(4))`

`d=(-8\pm√(64-48))/(8)`

`d=(-8\pm√(16))/(8)`

`d=(-8\pm4)/(8)`

So
`d=(-8+4)/(8)` and
`d=(-8-4)/(8)`

`d=-(1)/(2)` and
`d=-(3)/(2)`

Or
`d=-0.5` and
`d=-1.5`

∴
`d= -0.5, -1.5`