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A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows down and comes to a stop during a 10.0 s period. What was the girls acceleration at each of the three time periods?

1 Answer

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Answer:

1) The girl's acceleration at time 't' is,
a=0.47 m/s²

2) The girl's acceleration at time 't₁' is,
a_(1)=0 m/s²

3) The girl's acceleration at time 't₂' is,
a_(2)=-0.14 m/s²

Step-by-step explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'


a=(v-u)/(t)


a=(1.4-0)/(3)


a=0.47 m/s²

2) The girl's acceleration at time 't₁'


a_(1) =(v_(1) -v)/(t_(1))


a_(1)=(1.4-1.4)/(6)


a_(1)=0 m/s²

3) The girl's acceleration at time 't₂'


a_(2) =(v_(2) -v_(1))/(t_(2))


a_(2)=(0-1.4)/(10)


a_(2)=-0.14 m/s²

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