Question

Find the equation of the circle with center at (3,-2) and radius of 3.

a. (x - 3)2 + (y + 2)2 = 9
c. (x-3)2 + (y+ 2) = 3
b. (x+3)2 + (-2)2 = 9
d. (x+3)2 + (-2)2 = 3
Please select the best answer from the choices provided

Answer 1

`(x - 3) {}^(2) + (y + 2) {}^(2) = 3 {}^(2) \\ (x - 3) {}^(2) + (y + 2) {}^(2) = 9`

Answer: The A option is correct.

Good luck!

Intelligent Muslim,

From Uzbekistan.

Answer 2

equation of circle=(x-3)^2+(y+2)^2=9

Explanation:

given center of circle at (3,-2) and radius=3

equation of circle is
`(x-x_1)^2+(y-y_1)^2`=
`r^2`

where r=radius of circle,
`x_1`=3,
`y_1`=-2

eqution of circle=
`(x-3)^2+(y+2)^2=3^2`

eqution of circle=
`(x-3)^2+(y+2)^2`=9