Question

Acceleration calculations

1. What are the resultant forces acting on these objects?
acceleration
5 m/s
10 kg
force
miss actieration
a) An object of mass 10 kg accelerating at 5 m/s2 -

Answer 1

The resultant force acting on the object is,
`F_(r)` = 110 N

Step-by-step explanation:

Given data,

The acceleration of the object, a = 5 m/s²

The mass of the object, m = 10 kg

Let the acceleration be in the horizontal direction.

The force acting on the object,

Fₓ = m x a

= 10 x 5

= 50 N

The gravitational force acting on the object,

F = mg

= 10 x 9.8

= 98 N

The resultant force on the object will be,

`F_(r) =\sqrt{F_(x)^(2)+F^(2) +2 F_(x) F Cos \theta }`

`F_(r) =\sqrt{F_(x)^(2)+F^(2)` (∵ θ = 90°)

Substituting,

`F_(r) =\sqrt{50^(2)+98^(2)`

`F_(r)` = 110 N

Hence, the resultant force acting on the object is,
`F_(r)` = 110 N