Question

a party rental company has chairs and tables for rent. the total cost to rent 3 chairs and 8 tables is 55$. the total cost to rent 5 chairs and 2 tables is 18$. what is the cost to rent each chair and table?

Answer 1

Explanation:

3c+8t=$55; 5c+2t=$18. Solving the two simultaneously, using substitution methods, from equation 1

C=55-8t/3_____(3)_ put (3) in equation (2)

5(55-8t)/3 +2t =$18 ;multiplying both side by 3_ we have

5x55 - 5x8t + 3x2t = 18 x3

275 - 40t + 6t = 54

34t = 275 - 54

34t = 221

t = 221/34 the coefficient of t

t = $6.5 per table.

Therefore, substitute for t in (3) above

We have C = (55 - 8x6.5)/3

C= (55 - 52)/3; 3/3, =$1

Therefore the cost of a chair is $1 and the cost of a table is $6.5

Answer 2

Answer: rent each chair is $1.25 and the cost to rent each table is $8.50

Explanation:

Let C = cost to rent each chair

Let T = cost to rent each table

4C + 8T = 73

2C + 3T = 28

Multiply the 2nd equation by (-2) and then add the equations together

4C + 8T = 73

-4C - 6T = -56

2T = 17

T = 17/2 = 8.5

Plug this in to the 1st equation to solve for C

4C + 8(17/2) = 73

4C + 68 = 73

4C = 5

C = 5/4 = 1.25

Hope this helps!!!