Final Answer:
a. With a calculated t-value of t_(39) = -1.93 and a critical t-value of ±2.71 at a .01 significance level (two-tailed test), we fail to reject the null hypothesis. There isn't enough evidence to conclude a significant change in driving speed after the installation of the school speed limit sign.
c. The 99% confidence interval for the mean difference in driving speed is (-4.67, 0.67) mph.
Explanation:
a. To conduct the hypothesis test, we set up the null hypothesis H₀: μ₁ - μ₂ = 0 (there's no change in driving speed) against the alternative hypothesis H₁: μ₁ - μ₂ ≠ 0 (there's a change in driving speed). Given the sample mean difference of
mph, with a sample size (n) of 40 and a standard deviation (σ) of 7.5 mph, the calculated t-value is
, where s is the pooled standard deviation. The calculated t-value is -1.93. Comparing this to the critical t-value of ±2.71 (two-tailed test) at a .01 significance level and degrees of freedom df = 39, we fail to reject the null hypothesis.
c. The 99% confidence interval for the mean difference in driving speed is calculated using the formula
, where
is the critical value at a 99% confidence level. For a two-tailed test at α = 0.01 and degrees of freedom df = 39, the critical t-value is ±2.71. Plugging in the values, we find the confidence interval for the mean difference in driving speed to be (-4.67, 0.67) mph. This interval includes zero, further supporting the lack of a significant change in driving speed after the installation of the school speed limit sign.