To solve this problem it is necessary to apply the kinematic equations of movement description, where the speed of a body is defined as the distance traveled in a given time, that is to say
![v = (x)/(t)](https://img.qammunity.org/2020/formulas/physics/college/k7ofbrwmtgz5j9e9exhev8e155xt50te21.png)
where,
x = Displacement
t = time
Since the moon is making a path equal to that of a circle, we know by geometry that the perimeter of a circle is given by
![x = 2\pi r](https://img.qammunity.org/2020/formulas/physics/college/3auofrxxnpporjnyihrigs3caee71h7ovw.png)
![x = 2\pi (3.8*10^8)](https://img.qammunity.org/2020/formulas/physics/college/nf4wpydlctdoxv9m1qqld2yawilvbjvghi.png)
![x=2.39*10^9m](https://img.qammunity.org/2020/formulas/physics/college/vzx5aeycx7kw50eaybjth5zerkyb2hp6sc.png)
At the same time we have that time is equal to
![t = 28days((86400s)/(1day))](https://img.qammunity.org/2020/formulas/physics/college/3z8g8pd7x04g8mgr8edjv9ive6s3ukvnkw.png)
![t = 2419200s](https://img.qammunity.org/2020/formulas/physics/college/q9dt8muffyt9k1z9udgzeyier2q202pzde.png)
Using the equation for velocity we have finally that
![v= (x)/(t)](https://img.qammunity.org/2020/formulas/physics/college/mxi61rxijwukks2pq2izkmbbms0mc4xxs8.png)
![v = (2.39*10^9)/(2419200)](https://img.qammunity.org/2020/formulas/physics/college/3cwhur7eel7gy9zioq2uses8ya6zq12l32.png)
![v = 987.92 m/s](https://img.qammunity.org/2020/formulas/physics/college/wm5qt297lnaj9q40c4ukjhybxxjf20b3a5.png)
Therefore the speed of the Moon in its orbit is 987.92m/s