Question

A beaker has 300g.of an unknown compound. The compound contains 46.67% carbon,

4.45% hydrogen, 31.1% nitrogen, and 17.8% oxygen. The molecular formula of the
compound has a molar mass of 180 g/mol. How many atoms are in the beaker?
please help

Answer 1

Mr Carbon = 0.4667 • 180 = 84 g/mol

No. of Carbon = 84 / 12 = 7 atom

Mr Hydrogen = 0.0445 • 180 = 8 g/mol

No. of Hydrogen = 8 / 1 = 8 atom

Mr Nitrogen = 0.311 • 180 = 56 g/mol

No. of Nitrogen = 56 / 14 = 4 atom

Mr Oxygen = 0.178 • 180 = 32 g/mol

No. of Oxygen = 32 / 16 = 2 atom

Compound = C7H8N4O2

Total Atoms = 7 + 8 + 4 + 2

Total Atoms = 21 atom