Answer:
Molecular formula is N₄O₁₀
Step-by-step explanation:
We are given;
- Mass of the oxide of nitrogen as 108 g
- Mass of nitrogen as 4.02 g
- Mass of Oxygen is 11.48 g
We are required to calculate the molecular formula of the compound.
Step 1: Determine the number of moles of Nitrogen and Oxygen
Atomic mass of Nitrogen as 14.0 g/mol
Moles = Mass ÷ Atomic mass
Therefore;
Moles of Nitrogen = 4.02 g ÷ 14.0 g/mol
= 0.287 moles
Moles of Oxygen
Atomic mass of oxygen as 16.0 g/mol
Moles of Oxygen = 11.48 g ÷ 16.0 g/mol
= 0.7175 moles
Step 2: Determine the simplest whole number mole ratio
The mole ratio of N : O will be;
O.287 moles : 0.7175 moles
1 : 2.5
Multiplying by 2 , we get
2 : 5
Therefore, the empirical formula of the nitrogen oxide is N₂O₅
Step 3: Determine the molecular formula of nitrogen oxide
Molecular formula = (empirical formula)n
Mass = 108 g
(N₂O₅)n = 108 g
((14×2) + (16 ×2))n = 108
60n = 108
n = 1.8
= 2
Thus, Molecular formula = (N₂O₅)2
= N₄O₁₀
Therefore, the molecular formula is N₄O₁₀