Question

A person pulls on a 7.4 kg crate against a 22 Newton frictional force, using a rope attached to the center of the crate. If the The crate began with a speed of 1.6 m/s and speeded up to 2.6 m/s while being pulled a horizontal distance of 2.0 meters. What is the work in J done by the force applied by the rope on the crate?

Answer 1

Work done will be 59.54 J

Step-by-step explanation:

We have given that person pulls a 7.4 kg crate against 22 Newton frictional force

So frictional force
`f=22N`

Balance force is given by
`F-f=ma`

We have given initial speed u = 1.6 m /sec

And final speed v = 2.6 m/sec

Distance s = 2 m

From third equation of motion we know that

`v^2=u^2+2as`

`2.6^2=1.6^2+2* a* 2`

`a=1.05m/sec^2`

So
`F-22=7.4* 1.05`

`F-22=7.4* 1.05`

We know that work done is given by

`W=Fs=29.77* 2=59.54J`