Question

Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 StartRoot 2 EndRoot Over 4 EndFraction

Answer 1

A

Explanation:

Answer 2

`y = (3 + 6√(2) )/(4)` and
`y = (3 - 6√(2) )/(4)`

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction

Explanation:

The given quadratic equation is (4y - 3)² = 72

We have to solve this equation for y.

Now, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒
`y = (3 + 6√(2) )/(4)` and
`y = (3 - 6√(2) )/(4)`

Therefore, the solution is y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction (Answer)