Question

Using a force of 200N, a hockey player does 500 J of work horizontally

onto a puck that started from rest on frictionless ice. How far did the puck
travel?

Answer 1

The displacement is 2.5 meters

Step-by-step explanation:

The formula for work is: W = Fs, where "W" is work, "F" is force, and "s" is displacement.

Since displacement is the shortest distance from start to finish, and the puck travels in a straight line, in this case, displacement = distance traveled.

Let's apply the formula:

`W = Fs\\500J = 200N s\\(500J)/(200N) = s\\2.5 m = s`

The displacement is 2.5 meters