Question

What is the distance between pints (-2 -5) and (3 -6)

Answer 1

`\displaystyle d = √(26)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra II

• Distance Formula:
  `\displaystyle d = √((x_2-x_1)^2+(y_2-y_1)^2)`

Explanation:

Step 1: Define

Point (-2, -5)

Point (3, -6)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [DF]:
   `\displaystyle d = √((3--2)^2+(-6--5)^2)`
2. (Parenthesis) Simplify:
   `\displaystyle d = √((3+2)^2+(-6+5)^2)`
3. (Parenthesis) Add:
   `\displaystyle d = √((5)^2+(-1)^2)`
4. [√Radical] Exponents:
   `\displaystyle d = √(25+1)`
5. [√Radical] Add:
   `\displaystyle d = √(26)`