Question

Write an equation in slope-intercept form of the line that passes through the points (8,2) and is parallel to the graph of the equation y=4x-3.

Answer 1

Slope-intercept form is y= 4x - 30

Explanation:

Step 1: Substitute the slope from original line into the equation of the line

Here slope , m is 4

y= mx +b

where

m is the slope

b is the y intercept

So Substituting slope we get,

y= 4x +b--------------------------------------------(1)

Step 2 :Substitute the given point (8,2) into the x and y values of equation (1)

y = 4x +b

2 =4(8) + b

Step 3: Solve for y intercept values

2 = 32+ b

2-32 =b

-30 =b

Now the y intercept value b= -30

Step 3: Substitute this value for 'b' in the slope intercept form equation

Substituting the value in eq (1) we get,

y= 4x +(-30)

y= 4x - 30