Question

Which is the balanced single displacement reaction between Aluminum (Al3+) and Copper Sulfate (Cu2+(SO4)2-)

Al + Cu(SO4) --> Cu + Al(SO4)

Al + Cu(SO4) --> Cu + Al2(SO4)3

2Al + 3Cu(SO4) --> 3Cu + Al2(SO4)3

Al2 + Cu(SO4)3 --> Cu + Al2(SO4)3

Answer 1

2Al + 3Cu(SO4) --> 3Cu + Al2(SO4)3

Step-by-step explanation:

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Answer 2

The balanced single displacement reaction between aluminum and copper sulphate is as follows.

`2Al(s)+3CuSO_(4)(aq)\rightarrow Al_(2)(SO_(4))_(3)(aq)+3Cu(s)`

Step-by-step explanation:

The given ions are as follows.

`Al^(3+)`- Aluminium ion and copper sulfate ion.

Single displacement reaction occurs one element replaces another element.

Hence, the balanced chemical reaction is as follows.

`2Al(s)+3CuSO_(4)(aq)\rightarrow Al_(2)(SO_(4))_(3)(aq)+3Cu(s)`

Oxidation half reaction:

`Al\rightarrow Al^(3+)+3e^(-)`

Aluminium loses three electrons.

Reduction half reaction:

`Cu^(2+)+2e^(-)\rightarrow Cu(s)`

Copper gain three electrons.