Question

A line is perpendicular to y = -x + 1

and intersects the point (-5,1).
What is the equation of this
perpendicular line?

Answer 1

Answer: The equation of the perpendicular line intersects the point (-5,1) is y=x+6[/tex]

Explanation:

step1:-

The standard form of slope - intercept form y=m x+c

Here m is called slope of the given line

C is called the y- intercept of the given line

Given equation of the straight line y=-x+1

comparing the slope - intercept form y=m x+c

here m= -1 and c=1

step2:-

The equation of the perpendicular line is

`y-{[y_(1)`} =\frac{-1}{m} (x-x_{1} )[/tex]

substitute m = -1 and c =1 values in equation

`y-1 =(-1)/(-1) (x-(-5 )`

`y-1 ={1} (x-(-5 )`

`y=1+x+5</strong></p><p><strong>\\y=x+6`

step3:- The equation of the perpendicular line intersects the point (-5,1) is

y=x+6[/tex]

conclusion:-

The equation of the perpendicular line is

y=x+6[/tex]