Answer:
![x=36](https://img.qammunity.org/2020/formulas/mathematics/high-school/dsk2dktzxv8nkynzews4bnf4v2u011wytt.png)
![y=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jhtozgvvhmtz2zmnl0yecx99jhilzs0e6k.png)
Explanation:
Let x be the large number and y be the small number.
Given:
The sum of two numbers is 40.
So the first relation is.
---------(1)
The large value is divided by smaller value.
So,
, and the quotient is 5 and the remainder is 4.
and second relation is.
![(x)/(y) =5+(4)/(y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8sh75mrm4xyxo409dtunib7uysxvmzm79s.png)
![(x)/(y) =(5y+4)/(y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m9v3xw026nt0dpxz5psr977lphqilcdsii.png)
The denominator y is cancelled both side.
![x = 5y + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hjm0nbtevuha04g5tgl49jbgtsupucc15c.png)
x value put in the equation 1
![5y+4+y=40](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w49r4y8sju5wwy904figiij2vcjvhbdet6.png)
![6y=40-4\\y=(36)/(6) \\y=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dmud03z93wmz4ndfnkqhljgb4mfsb07okj.png)
Put y value in equation 1
![x+6=40](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jtisk9eizl4m2smfyfoovo1ltinxqcmh0q.png)
![x=40-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d5hl7zd1cthpkwwmhwpcepe9i58annsqb0.png)
![x=36](https://img.qammunity.org/2020/formulas/mathematics/high-school/dsk2dktzxv8nkynzews4bnf4v2u011wytt.png)
Therefore, x value is 36 and y value is 6.