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The sum of two numbers is 40. If the larger is divided by the smaller, the quotient is 5 and the remainder is 4. Find the number.

User Zdebra
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1 Answer

3 votes

Answer:


x=36


y=6

Explanation:

Let x be the large number and y be the small number.

Given:

The sum of two numbers is 40.

So the first relation is.


x+y=40---------(1)

The large value is divided by smaller value.

So,
(x)/(y), and the quotient is 5 and the remainder is 4.

and second relation is.


(x)/(y) =5+(4)/(y)


(x)/(y) =(5y+4)/(y)

The denominator y is cancelled both side.


x = 5y + 4

x value put in the equation 1


5y+4+y=40


6y=40-4\\y=(36)/(6) \\y=6

Put y value in equation 1


x+6=40


x=40-6


x=36

Therefore, x value is 36 and y value is 6.

User Stefan Hoth
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