Question

Suppose a ball of putty moving horizontally with 1 kg·m/s of momentum collides with and sticks to an identical ball of putty moving vertically with 1 kg·m/s of momentum. What is the magnitude of their combined momentum?

Answer 1

The magnitude of their combined momentum would be 1.41 kg m/s

Step-by-step explanation:

I'm not sure why that is just the correct answer. Sorry.

Answer 2

`P=√(2)\ kg.m/s`

Step-by-step explanation:

Given that

For the first ball ,linear momentum P₁ = 1 kg.m/s (Horizontal)

For the second ball ,linear momentum P₂ = 1 kg.m/s ( vertically)

Lets take balls are moving in the x-y plane

As we know that linear momentum is a vector quantity

P₁ = 1 i kg.m/s

P₂ = 1 j kg.m/s

There combine linear momentum

P= P₁ + P₂

P = 1 i + 1 j kg.m/s

The magnitude of the linear momentum P

`P=√(1^2+1^2)\ kg.m/s`

`P=√(2)\ kg.m/s`