Question

Evaluate 8a+3b-10+c^28a+3b−10+c 2 8, a, plus, 3, b, minus, 10, plus, c, squared when a=2a=2a, equals, 2, b=5b=5b, equals, 5, and c=4c=4c, equals, 4.

Answer 1

its 37

Explanation:

Answer 2

Final answer is 37 after evaluating.

Explanation:

The given equation is,
`8 a+3 b-10+c^(2)`

Here a= 2, b=5, c = 4

We need to evaluate the equation.

Substituting the values in the equation we get,

`8 a+3 b-10+c^(2)`

`=(8 * 2)+(3 * 5)-10+4^(2)`

Using Multiplication property we get;

`= 16 +15 -10 +16`

Using addition property and subtraction property we get,

`=32 +5`

On simplifying equation using addition property we get,

`=37`

Hence Final answer is 37 after evaluating.