Question

A mosquito flaps its wings 600 vibrations per second which produces the annoying 600Hz buzz. The speed of sound is 340 m/s. How far does the sound travel between wing beats?

Answer 1

`\lambda=0.57m`

Step-by-step explanation:

The distance traveled by the sound wave between the beats of the wing is its wavelength, since it is defined as the distance traveled by a periodic disturbance that propagates in a cycle, is defined as:

`\lambda=(v)/(f)`

Where v is the speed of sound and f the frequency of the wing beats

`\lambda=(340(m)/(s))/(600Hz)\\\lambda=0.57m`