Answer:
The probability of rolling a number less than 6 on 1 roll of a die is
= 0.833is
Explanation:
Let
S be the sample space for a rolling of a Die
∴ is total number of outcomes for a rolling of a die are ={ one, two, three, four, five, six} six
i.e { 1,2,3,4,5,6}
∴ n (S) = 6
let A be the event of getting a number less than six
then the possible outcomes are { 1, 2, 3, 4, 5 }
∴ n(A) = 5
To Find:
P (A) = ?
Solution:
we know that probability is given by
![\textrm{probability of the event}=\frac{\textrm{possible outcomes of the event}}{\textrm{total number of outcomes}} \\\\\therefore P(A) = (n(A))/(n(S)) \\\\\therefore P(A) =(5)/(6)\\ \\\therefore P(A) = 0.833\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2xkdfl8n4cfyguq51e0gxxma5lhgjscbja.png)