11.7k views
1 vote
For the reaction A + B − ⇀ ↽ − C + D A+B↽−−⇀C+D , assume that the standard change in free energy has a positive value. Changing the conditions of the reaction can alter the value of the change in free energy ( Δ G ) (ΔG) . Classify the conditions as to whether each would decrease the value of Δ G ΔG , increase the value of Δ G ΔG , or not change the value of Δ G ΔG for the reaction. For each change, assume that the other variables are kept constant.a. Adding a catalystdecrease the free energy value, increase the free energy value, or not change the free energyb. increasing [C] and [D]decrease the free energy value, increase the free energy value, or not change the free energyc. Coupling with ATP hydrolysisdecrease the free energy value, increase the free energy value, or not change the free energyd.Increasing [A] and [B]decrease the free energy value, increase the free energy value, or not change the free energy

User Adan
by
5.6k points

2 Answers

2 votes

Answer:

a. Not change the free energy value

Step-by-step explanation:

User Ajan Balakumaran
by
6.6k points
6 votes

Answer:

a. Not change the free energy value

b. Increase the free energy value

c. Decrease the free energy value

d. Decrease the free energy value

Step-by-step explanation:

a. Adding a catalyst:

A catalyst is a substance that will reduce the activation energy of a reaction, it means that the reaction will occur fast. The values of enthalpy, entropy, and free energy are not affected by a catalyst, so ΔG remains the same.

b. Increasing [C] and [D]:

For a reversible reaction, the value of free energy can be calculated by:

ΔG = ΔG° + RT*lnK

Where ΔG° is the standard value for free energy, R is the gas constant, T is the temperature, and K is the constant of equilibrium, which in this case:

K = ([C]*[D])/([A]*[B])

When [C] and [D] increase, the value of K increases, and lnK also increases, then, the value of ΔG increases.

c. Coupling with ATP hydrolysis:

The free energy can be calculated by:

ΔG = ΔH - TΔS

Where ΔH is the change in enthalpy, and ΔS the change in entropy. The ATP hydrolysis is an exothermic reaction, so ΔH <0. When it is coupled, it will reduce the total value of ΔH, and because of that, the value of ΔG will decrease.

d. Increasing [A] and [B]:

As explained above, the increasing at [A] and [B] will decrease the value of K, so the value of lnK will decrease, and ΔG value will also decrease.

User WPInfo
by
5.7k points