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Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...

User HpTerm
by
7.8k points

2 Answers

3 votes

Answer:

Explanation:

User Sherif Ahmed
by
7.8k points
4 votes

Answer:


a_6_3=371

Explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference

we have


-1,5,11,...

Let


a_1=-1\\a_2=5\\a_3=11


a_2-a_1=5-(-1)=5+1=6


a_3-a_2=11-5=6

The common difference is
d=6

We can write an Arithmetic Sequence as a rule


a_n=a_1+d(n-1)

where

a_n is the nth term

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have


n=63\\d=6\\a_1=-1

substitute


a_6_3=-1+6(63-1)


a_6_3=-1+6(62)


a_6_3=-1+372


a_6_3=371

User Mansoor Akhtar
by
8.6k points

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