Question

If 255 J of heat is applied to 20.0 g of

gold, what temperature change will
occur if the specific heat of gold is 0.129 j/g C

Answer 1

ΔT = 98.84 °C

Step-by-step explanation:

Given data:

Heat absorbed = 255 J

Mass of gold = 20.0 g

Specific heat capacity of gold = 0.129 J/g.°C

Temperature change = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values,

255 J = 20.0 g × 0.129 J/g.°C × ΔT

255 J = 2.58 J / °C × ΔT

ΔT = 255 J / 2.58 J / °C

ΔT = 98.84 °C