Answer:
a. I₁ = 0.1171875 kg * m²
b. I₂ = 0.288 kg * m²
Step-by-step explanation:
a. m₁ = 2.5 kg, L₁ = 0.75 m
The rotational inertia about an axis perpendicular to it and passing through its center
I₁ = ¹/₁₂ * M * L²
I₁ = ¹/₁₂ * 2.5 kg * (0.75m)²
I₁ = 0.1171875 kg * m²
b. m₂ = 3 kg , d₁ = 0.38 m
The rotational inertia tangent to the edge of the sphere
I₂ = ²/₃ * M * R²
I₂ = ²/₃ * 3 kg * (0.38m)²
I₂ = 0.288 kg * m²