Question

Consider the following code: String word [] = {"algorithm", "boolean", "char", "double"}; for ( int i =0; i < word.length/2; i++) { word[i] = word[word.length - 1 - i]; } What is stored in word after running this code? algorithm algorithm algorithm algo

Answer 1

At the end of this code word array will hold {"double","char","char","double"}

Step-by-step explanation:

• The string word is an array of four strings {"algorithm","boolean","char","double"}.
• This means that the length of this array is 4.
• The for runs for half the length of array i.e. 2.

First Loop: (i = 0)

• For i = 0 word[0] = word[word.length - 1 - 0]
• Now here we will have word[0] = word [3] which is "double"

Second Loop (i = 1)

• For i = 1 word[1] = word[word.length - 1 - 1]
• Now here we will have word[1] = word [2] which is "char"

Rest of the array will remain the same hence the output will be:

word[] = {"double","char","char","double"}

Answer 2

{"double", "char", "char", "double"} will be stored in word.

Step-by-step explanation:

Given the word is an array of four strings, {"algorithm", "boolean", "char", "double"}. Hence, the length of the word array is 4.

The for-loop will only run for two iterations due to i < word.length/2, with i = 0 (first loop) and i = 1 (second loop).

In the first loop,

• word[word.length - 1 - i] = word[4 - 1 - 0] = word[3] = "double"
• Hence, the string "double" will be assigned to word[0] and overwrite "algorithm"

In the second loop,

• word[word.length - 1 - i] = word[4 - 1 - 1] = word[2] = "char"
• Hence, the string "char" will be assigned to word[1] and overwrite "boolean"

At last, the word array will hold {"double", "char", "char", "double"}