Question is Incomplete, Complete question is given below.
One evening 1500 concert tickets were sold for the Jazz Fest. Tickets cost $25 for covered pavilion seats and $15 for lawn seat. Total receipts were $28,500. How many of each type of ticket were sold?
Answer:
Number of Pavilion seat is 600 and number of lawn seats is 900.
Explanation:
Given:
Total Number of ticket sold = 1500
Let number of Pavilion seat be x.
Let number of lawn seats be y.
hence the equation can be framed as;
![x+y=1500 \ \ \ \ equation \ 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/6bsu3y627i4tp2l9ertjqj6fpjoqrhk5v5.png)
Also Given
Total Amount made = $28,500
Cost of pavilion seat = $25
Cost of lawn seat = $15
Total Amount made is equal to Cost of pavilion seat multiplied by number of Pavilion seat plus Cost of lawn seat multiplied by number of lawn seats.
![25x+15y = 28500](https://img.qammunity.org/2020/formulas/mathematics/high-school/hfas12ogd9ua59pvyttl2ehkzvsomvltj7.png)
Dividing by 5 on both side we get;
![5x+3y= 5700 \ \ \ \ equation \ 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/calgu5m8lby4e6ru6s6b0chirokhfn9ocs.png)
Now Multiplying equation by 3 we get;
![3(x+y)=1500*3\\3x+3y = 4500 \ \ \ \ equation \ 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/1yiovgr3auzzns62mw2y2rkvettqo0id1t.png)
Now Subtracting equation 3 from 2 we get;
![(5x+3y)-(3x+3y)=5700-4500\\5x+3y-3x-3y=1200\\2x=1200\\x=(1200)/(2)=600](https://img.qammunity.org/2020/formulas/mathematics/high-school/enazuqflerwqc26fryr3pr6pk7q78tpw73.png)
Substituting the value of x in equation 1 we get;
![x+y=1500\\600+y=1500\\y=1500-600\\y=900](https://img.qammunity.org/2020/formulas/mathematics/high-school/f6xokjvshih7ys0c16e3s7z23ezkumcfzl.png)
Hence Number of Pavilion seat is 600 and number of lawn seats is 900.