Answer:
After 11.25 hour Mrs. Caldwell catches Mr. caldwell
Explanation:
We have given that Mr. caldwell leaves 2.5 hour before Mrs. Caldwell.
Let the distance is d
When Mrs. Caldwell catches Mr. caldwell they will cover same distance as d
Speed of Mr. caldwell is 45 mph
And speed of Mrs. Caldwell. is 55 mph
Let time taken by Mrs. Caldwell is t
Then time taken by Mr. caldwell is t+2.5
So
![45(t+2.5)=t* 55](https://img.qammunity.org/2020/formulas/mathematics/high-school/ko6e319yxasikz1mkrp3zlvsdl5lhtxcs0.png)
![45t+112.5=55t](https://img.qammunity.org/2020/formulas/mathematics/high-school/exp4u93zftyls856eos7w2c0ob1xqe2f0t.png)
![t=11.25hour](https://img.qammunity.org/2020/formulas/mathematics/high-school/o2j1yj0fxn9vbp2jgu0lvn9pyfchpekqf8.png)
So after 11.25 hour Mrs. Caldwell catches Mr. caldwell