Question

Suppose 50.0g of silver nitrate is reacted with 50g of hydrochloric acid producing silver chloride and a mixture of other products. If the mass of the other products formed is 46.4 grams, how much silver chloride was produced?

Answer 1

53.6 grams of silver chloride was produced.

Step-by-step explanation:

`AgNO_3+HCl+\rightarrow AgCl+HNO_3`

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Mass of silver nitrate = 50.0 g

Mass of hydrogen chloride = 50.0 g

Mass of silver chloride = x

Mass of nitric acid = 46.4 g

Mass of silver nitrate + Mass of hydrogen chloride =

Mass of silver chloride + Mass of nitric acid

[te]50.0 g+50.0 g=x+46.4 g[/tex]

`x=50.0 g+50.0 g - 46.4 g = 53.6 g`

53.6 grams of silver chloride was produced.