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Given rectangle ABCD with vertices A(1, 4), B(3, 6), C(6, 3), and D(4, 1), what is the

perimeter of ABCD? Leave your answer in simplified radical form.

User Mseddon
by
5.2k points

1 Answer

4 votes

Answer:

10√2

Explanation:

A(1, 4), B(3, 6), C(6, 3), D(4, 1)

The distance formula tells you the distance d between two points (x1, y1) and (x2, y2) is given by ...

d = √((x2-x1)² +(y2-y1)²

Then the side lengths are ...

AB = √(2² +2²) = √8 = 2√2

BC = √(3² +(-3)²) = √18 = 3√2

The perimeter is twice the sum of these sides, so is ...

P = 2(2√2 +3√2) = 10√2 . . . the perimeter of the rectangle

User LanderV
by
5.8k points