81.2k views
3 votes
The length of a rectangle is increasing at a rate of 8 centimeters per second and its width is increasing at a rate of 3 centimeters per second. When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?

1 Answer

5 votes

Area of rectangle is increasing at 140 cm²/s when the length is 20 cm and the width is 10 cm.

Explanation:

Area = Length x Width

A = LW

Differentiating with respect to time


(dA)/(dt)=L(dW)/(dt)+W(dL)/(dt)

Length, L = 20 cm

Width, W = 10 cm


(dW)/(dt)=3cm/s\\\\(dL)/(dt)=8cm/s

Substituting


(dA)/(dt)=20* 3+10* 8\\\\(dA)/(dt)=60+80\\\\(dA)/(dt)=140cm^2/s

Area of rectangle is increasing at 140 cm²/s when the length is 20 cm and the width is 10 cm.

User Michiel Van Dijk
by
5.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.