Answer:
40·919 m
Step-by-step explanation:
Initial velocity of the arrow = 46 m/s
Angle at which it is thrown from horizontal = 38°
At the maximum height, the vertical component of velocity will be 0
Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s
From the formula
v² - u² = 2 × a × s
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
Considering the formula in vertical direction and taking upward direction as positive
v = 0
u = 28·32 m/s
a = - g = - 9·8 m/s²
Let s be the maximum height
- 28·32² = - 2 × 9.8 × s
⇒ s = 40·919 m
∴ The arrow will go 40·919 m high