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X^2 +7x +9=3 written as ax^2+bx+c=0

User Muetzerich
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1 Answer

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For this case we have the following quadratic equation:


x ^ 2 + 7x + 9 = 3

We must rewrite the equation as:


ax ^ 2 + bx + c = 0

So:

Subtracting 3 from both sides of the equation we have:


x ^ 2 + 7x + 9-3 = 0\\x ^ 2 + 7x + 6 = 0

So we have to:


a = 1\\b = 7\\c = 6

Answer:


x ^ 2 + 7x + 6 = 0

User Goutham Ganesan
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