Answer:
2/3 or 0.667
Explanation:
Since the bus arrival time is distributed uniformly in the interval from 10:00 and 10:30, 30 minutes. The probability that you will have to wait more than 10 minutes is 1 minus the probability you will have to wait 10 minutes or less. And since it's a distribution uniform, that probability is 10/30 = 1/3. So in the end, the probability that you will have to wait for more than 10 minutes is 1 - 1/3 = 2/3 or 0.667