Answer:
Average speed, v =1022.90 m/s
Step-by-step explanation:
Given that,
The average distance between the moon and the earth is,
![r=3.84* 10^8\ m](https://img.qammunity.org/2020/formulas/physics/high-school/k7qlknuwhayabk5wj1rhjfk4bc62ecoev1.png)
The period of revolution of the Moon,
![T=27.3\ days](https://img.qammunity.org/2020/formulas/physics/high-school/ink3876yw6jr6nzc2zdshq46ecnllgidov.png)
To find,
The average speed of the Moon around the Earth.
Solution,
If T is the orbital period and r is the orbital speed of the moon. The average speed is given by :
![v=r* \omega](https://img.qammunity.org/2020/formulas/physics/college/8fc92hhcnyxz2py9suat48vwgqb8cpazcs.png)
Where
is the angular speed
![v=r* (2\pi r)/(T)](https://img.qammunity.org/2020/formulas/physics/high-school/k58tnd1vu1pg31zcg35plpm6i5qte3bjd3.png)
Since, 1 day = 86400 seconds
27.3 days = 2358720 seconds
![v=r* (2\pi)/(T)](https://img.qammunity.org/2020/formulas/physics/high-school/46geo5jo4i3fgkuatlx8x8ow8fktcwwvqw.png)
![v=(2\pi * 3.84* 10^8)/(2358720)](https://img.qammunity.org/2020/formulas/physics/high-school/urztt7he2k97lbgdy8dewlh4r43wt3vikg.png)
v = 1022.90 m/s
or
So, the average speed of the Moon around the Earth is 1022.90 m/s.